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Exercise 10.3 · Q6

Q.Find the differential equations of the family of all the ellipses having foci on the yy-axis and centre at the origin.

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Differentiate the ellipse equation twice and eliminate both a2a^2 and b2b^2 exactly as Example 10.6 did for the foci-on-xx-axis case; the algebra is symmetric in the two constants, so the same differential equation results.

Step 1. Write the family. x2b2+y2a2=1\dfrac{x^2}{b^2}+\dfrac{y^2}{a^2}=1 (a>b>0a>b>0, so the foci lie on the yy-axis), with a,ba,b arbitrary.

Step 2. Differentiate once. 2xb2+2ya2dydx=0 ⟹ xb2+ya2dydx=0\dfrac{2x}{b^2}+\dfrac{2y}{a^2}\dfrac{dy}{dx}=0\ \Longrightarrow\ \dfrac{x}{b^2}+\dfrac{y}{a^2}\dfrac{dy}{dx}=0. …(2)

Step 3. Differentiate (2) again. 1b2+1a2[yd2ydx2+(dydx)2]=0 ⟹ 1b2=−1a2[yd2ydx2+(dydx)2]\dfrac{1}{b^2}+\dfrac{1}{a^2}\left[y\dfrac{d^2y}{dx^2}+\left(\dfrac{dy}{dx}\right)^2\right]=0\ \Longrightarrow\ \dfrac{1}{b^2}=-\dfrac{1}{a^2}\left[y\dfrac{d^2y}{dx^2}+\left(\dfrac{dy}{dx}\right)^2\right]. …(3)

Step 4. Also solve (2) for 1b2\dfrac1{b^2}. 1b2=−yx a2dydx\dfrac{1}{b^2}=-\dfrac{y}{x\,a^2}\dfrac{dy}{dx} (for x≠0x\ne0). …

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