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Question 56 of 69

Q.Solve the equation 2x3−9x2+10x=32x^3-9x^2+10x=3, if 1 is a root, find the other roots.

Puducherry TnboardTamil Nadu HSC (DGE) Board 2022Subjective· 3mImportance★★★★★
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Deflates the cubic by the known root x=1 via synthetic division, then solves the resulting quadratic for the remaining two roots.

  1. Rewrite the given equation in standard form: 2x3−9x2+10x−3=02x^3-9x^2+10x-3=0.
  2. Since x=1x=1 is given as a root, divide the cubic by (x−1)(x-1) using synthetic division with coefficients 2,−9,10,−32,-9,10,-3: Bring down 22; 2(1)=22(1)=2, add to −9-9 gives −7-7; −7(1)=−7-7(1)=-7, add to 1010 gives 33; 3(1)=33(1)=3, add to −3-3 gives 00 (confirming x=1x=1 is indeed a root).
  3. The quotient is 2x2−7x+3=02x^2-7x+3=0. …

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