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Question 62 of 69

Q.If α\alpha and β\beta are the roots of the quadratic equation 2x2−7x+13=02x^2-7x+13=0, construct a quadratic equation whose roots are α2\alpha^2 and β2\beta^2.

Puducherry TnboardTamil Nadu HSC (DGE) Board 2024Subjective· 2mImportance★★★★★
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Computes the sum and product of the squared roots from the sum/product of the original roots, then writes x2−(sum)x+(product)=0x^2-(\text{sum})x+(\text{product})=0.

  1. For 2x2−7x+13=02x^2-7x+13=0 with roots α,β\alpha,\beta: sum α+β=72\alpha+\beta=\dfrac{7}{2}, product αβ=132\alpha\beta=\dfrac{13}{2}.
  2. New sum: α2+β2=(α+β)2−2αβ=(72)2−2(132)=494−13=49−524=−34\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta=\left(\dfrac72\right)^2-2\left(\dfrac{13}2\right)=\dfrac{49}4-13=\dfrac{49-52}4=-\dfrac34.
  3. New product: α2β2=(αβ)2=(132)2=1694\alpha^2\beta^2=(\alpha\beta)^2=\left(\dfrac{13}2\right)^2=\dfrac{169}4. …

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