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Mathematics · Ch 5 — Two Dimensional Analytical Geometry-II

Parabola

5.3.2

Parabola

Since e=1e=1 for a parabola, a parabola is simply the set of points equidistant from a fixed focus and a fixed directrix.

(i) Standard form, vertex at the origin. Let SS be the focus and ℓ\ell the directrix; draw SZ⊥ℓSZ\perp\ell, and take the line SZSZ (produced) as the xx-axis with the perpendicular bisector of SZSZ as the yy-axis, so the origin OO is their intersection. Let SZ=2aSZ=2a, so S=(a,0)S=(a,0) and ℓ:x+a=0\ell:x+a=0. For a moving point P(x,y)P(x,y) with PM⊥ℓPM\perp\ell, the defining condition SP=PMSP=PM (since e=1e=1) gives

(x−a)2+y2=(x+a)2  ⟹  y2=4ax,(x-a)^2+y^2=(x+a)^2 \implies y^2=4ax,

the parabola in standard form. The three other origin-vertex orientations follow by symmetry: y2=−4axy^2=-4ax (opens left), x2=4ayx^2=4ay (opens up), x2=−4ayx^2=-4ay (opens down).

Vocabulary (Definition 5.3). The line through the focus perpendicular to the directrix is the axis; where the axis meets the curve is the vertex; any chord through the focus is a focal chord; the focal chord perpendicular to the axis is the latus rectum, and its endpoints for y2=4axy^2=4ax are (a,±2a)(a,\pm2a) (found by substituting x=ax=a), so its length is 4a4a. The parabola y2=4axy^2=4ax is symmetric about the xx-axis (replacing yy by −y-y leaves the equation unchanged) and lies entirely on the side x≥0x\ge0.

(ii) Vertex at (h,k)(h,k). Shifting the origin to (h,k)(h,k): when the axis is parallel to the xx-axis, the equation is (y−k)2=±4a(x−h)(y-k)^2=\pm4a(x-h); when parallel to the yy-axis, (x−h)2=±4a(y−k)(x-h)^2=\pm4a(y-k). Summarised (with a>0a>0 throughout):

EquationVertexFocusAxisDirectrixLatus rectum
(y−k)2=4a(x−h)(y-k)^2=4a(x-h)(h,k)(h,k)(h+a,k)(h+a,k)y=ky=kx=h−ax=h-a4a4a
(y−k)2=−4a(x−h)(y-k)^2=-4a(x-h)(h,k)(h,k)(h−a,k)(h-a,k)y=ky=kx=h+ax=h+a4a4a
Figure 5.17–5.18Parts of the parabola y^2 = 4ax opening to the right: vertex V(0,0), focus F(a,0), directrix x = -a, the axis of symmetry and the latus rectum LL'
Fig. 5.17–5.18 — Parts of the parabola y^2 = 4ax opening to the right: vertex V(0,0), focus F(a,0), directrix x = -a, the axis of symmetry and the latus rectum LL'

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Focus SS, directrix ℓ\ell, vertex, axis and the latus rectum LL′LL' through the focus perpendicular to the axis, for y2=4axy^2=4ax. …

Figure 5.19–5.22The four orientations of a parabola with vertex at (h,k): opening right (y-k)^2=4a(x-h), left (y-k)^2=-4a(x-h), up (x-h)^2=4a(y-k) and down (x-h)^2=-4a(y-k)
Fig. 5.19–5.22 — The four orientations of a parabola with vertex at (h,k): opening right (y-k)^2=4a(x-h), left (y-k)^2=-4a(x-h), up (x-h)^2=4a(y-k) and down (x-h)^2=-4a(y-k)

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Four small sketches — opening right, left, up and down — each showing the vertex (h,k)(h,k), the shifted focus and directrix for (y−k)2=±4a(x−h)(y-k)^2=\pm4a(x-h) and (x−h)2=±4a(y−k)(x-h)^2=\pm4a(y-k). …