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Exercises · 8.7

Q.On your birthday, you measure the activity of a sample of 210Bi^{210}\text{Bi} which has a half-life of 5.01 days. The initial activity that you measure is 1 μCi1\,\mu\text{Ci}.

(a) What is the approximate activity of the sample on your next birthday? Calculate
(b) the decay constant
(c) the mean life
(d) the initial number of atoms.
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Step 1 (decay constant, part b). λ=ln⁡2T1/2=0.69315.01×86400 s=0.69314.33×105≈1.6×10−6 s−1\lambda=\dfrac{\ln2}{T_{1/2}}=\dfrac{0.6931}{5.01\times86400\ \text{s}}=\dfrac{0.6931}{4.33\times10^5}\approx1.6\times10^{-6}\ \text{s}^{-1}.

Step 2 (mean life, part c). τ=1λ=T1/2/ln⁡2=5.01/0.6931≈7.23\tau=\dfrac{1}{\lambda}=T_{1/2}/\ln2=5.01/0.6931\approx7.23-7.247.24 days.

Step 3 (initial number of atoms, part d). From R0=λN0R_0=\lambda N_0, with R0=1 μCi=3.7×104R_0=1\ \mu\text{Ci}=3.7\times10^{4} Bq (since 1 Ci=3.7×10101\ \text{Ci}=3.7\times10^{10} Bq): N0=R0λ=3.7×1041.6×10−6≈2.31×1010N_0=\dfrac{R_0}{\lambda}=\dfrac{3.7\times10^4}{1.6\times10^{-6}}\approx2.31\times10^{10} atoms. …

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