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III. Long Answer Questions · Q8

Q.Sketch the static characteristics of a common emitter transistor and bring out the essence of input and output characteristics.

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Step 1 (Test circuit). All three curves are obtained from one circuit: bias supplies VBBV_{BB} (base loop) and VCCV_{CC} (collector loop) with rheostats to independently vary IBI_B and VCEV_{CE}/ICI_C, and meters to read IBI_B, ICI_C, VBEV_{BE} and VCEV_{CE}.

Step 2 (Input characteristics). Plotting IBI_B against VBEV_{BE} at several fixed VCEV_{CE} gives a curve resembling an ordinary forward diode characteristic, with a knee voltage near 0.7 V (silicon) / 0.3 V (germanium); increasing VCEV_{CE} shifts the curve slightly outward (narrower effective base width reduces IBI_B for the same VBEV_{BE}). Input impedance ri=(ΔVBE/ΔIB)VCEr_i=(\Delta V_{BE}/\Delta I_B)_{V_{CE}} is HIGH.

Step 3 (Output characteristics). Plotting ICI_C against VCEV_{CE} at several fixed IBI_B reveals four regions: SATURATION (near-ohmic rise near VCE=0V_{CE}=0), CUT-OFF (IB=0I_B=0, small residual leakage ICEOI_{CEO}), ACTIVE (nearly flat ICI_C, used for amplification, EB forward/CB reverse), and BREAKDOWN (beyond the rated VCEV_{CE}, ICI_C rises destructively). Output impedance ro=(ΔVCE/ΔIC)IBr_o=(\Delta V_{CE}/\Delta I_C)_{I_B} is LOW.

Step 4 (Transfer characteristics). Plotting ICI_C against IBI_B at fixed VCEV_{CE} gives an approximately straight line through a small intercept (ICEOI_{CEO}); its slope, β=(ΔIC/ΔIB)VCE\beta=(\Delta I_C/\Delta I_B)_{V_{CE}}, is the forward current gain, typically 50-200. …

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