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Exercises · 4.36

Q.Compare the relative stability of the following species and indicate their magnetic properties: O2O_2, O2+O_2^+, O2−O_2^- (superoxide), O22−O_2^{2-} (peroxide).

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Stability increases with bond order: O2+>O2>O2−>O22−O_2^+ > O_2 > O_2^- > O_2^{2-}. All except peroxide are paramagnetic due to unpaired electrons in π∗\pi^* orbitals.

Why Bond Order Governs Stability

The strength of a chemical bond—and therefore the stability of a molecule—depends on how many electrons occupy bonding versus antibonding orbitals. Bond order quantifies this balance:

Bond Order=12(electrons in bonding MOs−electrons in antibonding MOs)\text{Bond Order} = \frac{1}{2}(\text{electrons in bonding MOs} - \text{electrons in antibonding MOs})

A higher bond order means more net bonding character, a shorter and stronger bond, and greater stability. When we add or remove electrons from O2O_2, we change the bond order and thus the relative stability.

Magnetism follows directly from electron configuration: any species with unpaired electrons is paramagnetic (attracted to a magnetic field), while species with all electrons paired are diamagnetic.

Molecular Orbital Configuration of Oxygen Species

Oxygen (Z=8Z = 8) has 16 electrons in O2O_2. The molecular orbital diagram for second-period homonuclear diatomics places orbitals in this order:

σ1s<σ1s∗<σ2s<σ2s∗<σ2pz<π2px=π2py<π2px∗=π2py∗<σ2pz∗\sigma_{1s} < \sigma^*_{1s} < \sigma_{2s} < \sigma^*_{2s} < \sigma_{2p_z} < \pi_{2p_x} = \pi_{2p_y} < \pi^*_{2p_x} = \pi^*_{2p_y} < \sigma^*_{2p_z}

For our purposes, focus on the valence electrons (the inner σ1s\sigma_{1s}, σ1s∗\sigma^*_{1s}, σ2s\sigma_{2s}, σ2s∗\sigma^*_{2s} are filled and cancel out):

Valence MO filling for O2O_2 (12 valence electrons):

\sigma_{2p_z}^2 \, \pi_{2p_x}^2 \, \pi_{2p_y}^2 \, \pi^*_{2p_x}^1 \, \pi^*_{2p_y}^1

The two electrons in the degenerate π∗\pi^* orbitals remain unpaired (Hund's rule).

Now let's analyze each species systematically.


1. O2O_2 (neutral oxygen molecule)

Total valence electrons: 12

Configuration: \sigma_{2p_z}^2 \, \pi_{2p_x}^2 \, \pi_{2p_y}^2 \, \pi^*_{2p_x}^1 \, \pi^*_{2p_y}^1

  • Bonding electrons: 2+2+2=62 + 2 + 2 = 6
  • Antibonding electrons: 1+1=21 + 1 = 2

Bond Order=12(6−2)=2\text{Bond Order} = \frac{1}{2}(6 - 2) = 2

Magnetic property: Two unpaired electrons → paramagnetic


2. O2+O_2^+ (dioxygen cation)

Total valence electrons: 11 (one electron removed from O2O_2)

The electron is removed from the highest-energy occupied orbital, a π∗\pi^* orbital:

Configuration: \sigma_{2p_z}^2 \, \pi_{2p_x}^2 \, \pi_{2p_y}^2 \, \pi^*_{2p_x}^1 \, \pi^*_{2p_y}^0

  • Bonding electrons: 6
  • Antibonding electrons: 1

Bond Order=12(6−1)=2.5\text{Bond Order} = \frac{1}{2}(6 - 1) = 2.5

Magnetic property: One unpaired electron → paramagnetic

Tip

Removing an electron from an antibonding orbital actually strengthens the bond. This is why O2+O_2^+ is more stable than O2O_2.


3. O2−O_2^- (superoxide ion)

Total valence electrons: 13 (one electron added to O2O_2)

The extra electron goes into a π∗\pi^* orbital:

Configuration: \sigma_{2p_z}^2 \, \pi_{2p_x}^2 \, \pi_{2p_y}^2 \, \pi^*_{2p_x}^2 \, \pi^*_{2p_y}^1

  • Bonding electrons: 6
  • Antibonding electrons: 3 …

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