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NCERT Exemplar · Q10

Q.A solution is to be kept between 40∘C40^\circ\text{C} and 45∘C45^\circ\text{C}. What is the range of temperature in degree fahrenheit, if the conversion formula is F=95C+32F = \dfrac{9}{5}C + 32?

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Apply the linear conversion formula to both boundary temperatures; since the function is increasing, the Fahrenheit range preserves the order of the Celsius endpoints, giving 104°F104°\text{F} to 113°F113°\text{F}.

The conversion formula F=95C+32F = \frac{9}{5}C + 32 is a linear function with a positive slope. This means temperature scales monotonically: as Celsius increases, Fahrenheit increases proportionally. When we have a range in Celsius, we simply convert each endpoint to find the corresponding Fahrenheit range.

Why does this work? Linear functions preserve order. The coefficient 95>0\frac{9}{5} > 0 ensures that if C1<C2C_1 < C_2, then F1<F2F_1 < F_2. So the minimum Celsius temperature maps to the minimum Fahrenheit temperature, and likewise for the maximum.

Step-by-step conversion:

  1. Identify the Celsius range.

    The solution must stay between 40°C40°\text{C} and 45°C45°\text{C}, so C∈[40,45]C \in [40, 45].

  2. Convert the lower bound C=40°CC = 40°\text{C}.

    Substitute into the formula:

F=95(40)+32=3605+32=72+32=104°FF = \frac{9}{5}(40) + 32 = \frac{360}{5} + 32 = 72 + 32 = 104°\text{F}

  1. Convert the upper bound C=45°CC = 45°\text{C}. …

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