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NCERT Exemplar · Q15

Q.Given that xx, yy and bb are real numbers and x<yx < y, b<0b < 0, then
(A) xb<yb\dfrac{x}{b} < \dfrac{y}{b}
(B) xb≤yb\dfrac{x}{b} \le \dfrac{y}{b}
(C) xb>yb\dfrac{x}{b} > \dfrac{y}{b}
(D) xb≥yb\dfrac{x}{b} \ge \dfrac{y}{b}

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When both sides of an inequality are divided by a negative number, the direction of the inequality sign must be reversed. Given x<yx < y and b<0b < 0, dividing by bb changes x<yx < y to xb>yb\dfrac{x}{b} > \dfrac{y}{b}. The correct option is (C).

Understanding how inequalities behave when you perform operations on them is fundamental. The key concept here revolves around what happens when you multiply or divide an inequality by a negative number.

Think about a simple number line. If you have two numbers, say 22 and 55, we know that 2<52 < 5.

Now, let's multiply both by a positive number, for example, 33:

2×3=62 \times 3 = 6

5×3=155 \times 3 = 15

The inequality 6<156 < 15 still holds true. The direction of the inequality sign remains the same.

However, consider what happens when you multiply or divide by a negative number. Let's take our original 2<52 < 5 and multiply both sides by −1-1:

2×(−1)=−22 \times (-1) = -2

5×(−1)=−55 \times (-1) = -5

Now, compare −2-2 and −5-5. On the number line, −2-2 is to the right of −5-5, which means −2-2 is greater than −5-5.

So, −2>−5-2 > -5.

Notice that the original inequality sign (<<) has flipped to (>>). This is a crucial rule for inequalities.

If A<BA < B and C<0C < 0 (i.e., CC is a negative number), then A⋅C>B⋅CA \cdot C > B \cdot C and AC>BC\dfrac{A}{C} > \dfrac{B}{C}.

Similarly, if A>BA > B and C<0C < 0, then A⋅C<B⋅CA \cdot C < B \cdot C and AC<BC\dfrac{A}{C} < \dfrac{B}{C}.

This rule applies because multiplying or dividing by a negative number essentially "reflects" the numbers across zero on the number line, reversing their relative order.

Let's apply this to the given problem.

  1. Start with the given inequality:

    We are given that xx and yy are real numbers such that x<yx < y.

  2. Identify the operation and the condition:

    We need to compare xb\dfrac{x}{b} and yb\dfrac{y}{b}. This means we are dividing both sides of the inequality x<yx < y by bb.

    We are also given a critical condition: b<0b < 0. This tells us that bb is a negative number.

  3. Apply the rule for dividing by a negative number: …

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