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Exercise 5.1 · Q22

Q.To receive Grade 'A' in a course, one must obtain an average of 90 marks or more in five examinations (each of 100 marks). If Sunita's marks in first four examinations are 87, 92, 94 and 95, find minimum marks that Sunita must obtain in fifth examination to get grade 'A' in the course.

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To find the minimum fifth-exam score needed for a 90+ average, treat the problem as a weighted average where each exam has equal weight. The required total is 5×90=4505 \times 90 = 450, and Sunita already has 87+92+94+95=36887+92+94+95 = 368. She needs at least 450−368=82450 - 368 = 82 marks.

The core idea here is the weighted average — but since all five exams carry equal weight (each out of 100), this simplifies to a simple arithmetic mean. The condition "average of 90 or more" means the sum of all five marks must be at least 5×90=4505 \times 90 = 450. That's the target total.

Think of it like this: the average is just the total divided by the number of items. If you know the total you need and the total you already have, the gap tells you exactly what the last piece must be. No fancy formulas needed — just addition and subtraction.

Let's work through it step by step.

  1. Find the required total marks. For an average of at least 90 across 5 exams:

Required total=5×90=450\text{Required total} = 5 \times 90 = 450

  1. Add up Sunita's marks from the first four exams.

87+92+94+95=36887 + 92 + 94 + 95 = 368

  1. Let xx be the marks in the fifth exam. The condition for grade 'A' is:

87+92+94+95+x5≥90\frac{87 + 92 + 94 + 95 + x}{5} \geq 90

  1. Multiply both sides by 5 (since 5 > 0, inequality direction stays the same):

368+x≥450368 + x \geq 450

  1. Solve for xx:

x≥450−368=82x \geq 450 - 368 = 82

So Sunita must score at least 82 in the fifth exam. …

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