Q.Find all pairs of consecutive even positive integers, both of which are larger than 5 such that their sum is less than 23.
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Linear Inequalities
Linear Inequalities: The Intuition First
You already know what an equation is: a statement that two things are exactly equal. 2x+3=7 says "twice something plus three is exactly seven." That's a tight, precise condition — only one number (x=2) satisfies it.
Now imagine you loosen that condition. Instead of "exactly equal to 7," what if you said "less than 7"? Or "greater than or equal to 7"? That's an inequality. You're no longer looking for a single point; you're looking for a whole range of numbers.
Real life is full of inequalities: "You need at least 60% to pass" (marks≥60), "The bus can carry at most 50 people" (passengers≤50), "Profit must be more than zero" (P>0). Equations are rare; inequalities are everywhere.
The Four Symbols
There are only four inequality symbols. Memorise them once:
| Symbol | Meaning | Example | Reads as |
|---|---|---|---|
| < | less than | x<5 | x is less than 5 |
| > | greater than | x>5 | x is greater than 5 |
| ≤ | less than or equal to | x≤5 | x is at most 5 |
| ≥ | greater than or equal to | x≥5 | x is at least 5 |
The "or equal to" versions (≤, ≥) include the boundary number itself. The strict versions (<, >) do not.
Solving Linear Inequalities: Almost Like Equations
A linear inequality looks just like a linear equation, but with an inequality sign instead of an equals sign. For example:
2x+3<7
You solve it the same way you solve 2x+3=7 — with one critical difference.
The Golden Rule (and the only trap)
When you multiply or divide both sides of an inequality by a negative number, you must flip the inequality sign.
Why? Think of the number line. 3<5 is true. Multiply both sides by −1: −3<−5? No — −3 is actually greater than −5 (because −3 is to the right on the number line). So the inequality flips: −3>−5.
This is the single most common mistake students make. If you multiply or divide by a negative, flip the sign. If you multiply/divide by a positive, leave it alone.
Example: Solve 2x+3<7
Step 1: Subtract 3 from both sides (no sign change — subtracting is always safe).
2x<4
Step 2: Divide both sides by 2 (positive — no flip).
x<2
Answer: Any number less than 2 works. x=1.9, x=0, x=−100 — all satisfy the original inequality.
Example: Solve −3x+5≥11
Step 1: Subtract 5 from both sides.
−3x≥6
Step 2: Divide both sides by −3 (negative — flip the sign).
x≤−2
Answer: x must be less than or equal to −2.
Representing Solutions: The Number Line
The solution to an inequality is an interval (or union of intervals), not a single number. You can show it on a number line:
- Open circle at a number means that number is not included (< or >).
- Closed circle means it is included (≤ or ≥).
- Shade the region that satisfies the inequality.
For x<2: open circle at 2, shade everything to the left.
For x≤−2: closed circle at -2, shade everything to the left.
The Precise Definition
A linear inequality in one variable is any inequality that can be written in one of these four forms:
ax+b<0,ax+b>0,ax+b≤0,ax+b≥0 …
Concept: Linear Inequalities
Let the two consecutive even positive integers be n and n+2, where n is even.
The condition "both larger than 5" gives n>5, so n≥6 (since n is even).
The condition "sum less than 23" gives:
n+(n+2)<23
2n+2<23
2n<21
n<10.5
Since n is even, we have n≤10. …
Let the first even integer be x; the next is x+2. With x>5 and x+(x+2)<23, the valid pairs are (6,8), (8,10), and (10,12).
Setting up the conditions. Let the smaller consecutive even integer be x, so the larger is x+2. The problem requires:
- both larger than 5: since x>5 automatically makes x+2>5, the binding condition is x>5;
- their sum less than 23: x+(x+2)<23.
Solving the sum inequality.
x+(x+2)<23
2x+2<23
2x<21
x<10.5
Combining the conditions.
5<x<10.5
Since x must be an even integer, the possible values are x=6, 8, 10, giving: …
- CA Foundation 2026Set jan-20261 markMCQQ.The solution of the inequality 35−2x≤6x−5 is (A) x≥8 (B) x≤8 (C) x≥6 (D) x≤6
›Reveal solutionSolution
Multiplying 35−2x≤6x−5 by 6 gives 40≤5x, i.e. x≥8.
Step 1 — clear denominators (LCM = 6)
6⋅35−2x≤6(6x−5) ⇒ 2(5−2x)≤x−30.
Step 2 — expand and collect
10−4x≤x−30 ⇒ 10+30≤x+4x ⇒ 40≤5x.
Step 3 — isolate x
x≥8.
Dividing by the positive 5 keeps the inequality sign unchanged. …
- CA Foundation 2026Set may-20261 markMCQQ.One experienced person does 10 units of work per day, while a fresher does 5 units of work per day. The employer wants to maintain at least 50 units of work per day. This situation can be expressed as ______ (A) 10x+5y>50 x≥0, y≤0 (B) 10x+5y≤50 x≥0, y≥0 (C) 10x+5y≥50 x≥0, y≥0 (D) 10x+5y=50 x≥0, y≤0
›Reveal solutionSolution
"At least 50" translates to ≥, and both counts of people are non-negative: 10x+5y≥50, x≥0, y≥0.
Step 1 — Define the variables
Let x= number of experienced persons and y= number of freshers.
Step 2 — Write the output
Each experienced person does 10 units and each fresher 5 units, so total daily output is 10x+5y.
Step 3 — Translate the constraints
"Maintain at least 50 units" means the output must be 50 or more:
10x+5y≥50
The number of people cannot be negative, so:
x≥0,y≥0 …
- CA Foundation 2025Set may-20251 markMCQQ.The longest side of a triangle is 2 times the shortest side and the third side is 4 cm shorter than the longest side. If the perimeter of the triangle is at least 61 cm, find the minimum length of the shortest side. (A) 7 cm (B) 9 cm (C) 11 cm (D) 13 cm
›Reveal solutionSolution
5s−4≥61⇒s≥13, so the shortest side is at least 13 cm.
Step 1 — Express all sides via the shortest side s
- Shortest = s
- Longest = 2s
- Third = longest −4=2s−4
Step 2 — Write the perimeter inequality
'Perimeter at least 61 cm' means
s+2s+(2s−4)≥61
5s−4≥61
Step 3 — Solve the inequality
5s≥65⇒s≥13
The smallest permissible value is s=13 cm (sides then 13, 26, 22 — a valid triangle since 13+22>26).
Why the other options are wrong: (A) 7, (B) 9, (C) 11 all give a perimeter below 61 cm, violating the condition. …
- CA Foundation 2025Set sep-20251 markMCQQ.Which of the followings is a solution of the inequality 35x≤6x−5 ? (A) (−∞,−310] (B) (−∞,−310) (C) (−∞,−38] (D) (−∞,−38)
›Reveal solutionSolution
Multiply out by 6, isolate x: x≤−310, endpoint included.
Step 1 — Remove the fractions
Multiply every term of 35x≤6x−5 by 6 (positive, so the direction is unchanged):
10x≤x−30.
Step 2 — Isolate x
10x−x≤−30⇒9x≤−30⇒x≤−930=−310.
Step 3 — Write the solution set
Because the sign is ≤, −310 belongs to the set: (−∞,−310]. …
- CA Foundation 2024Set sep-20241 markMCQQ.A dietician recommends mixture of two kinds of foods to a person so that mixture contains at least 45 units of carbs, 25 units of protein, 15 units of fat and 15 units of fibre. The above contents of nutrients are available in the foods as below :If 'x' units of food-1 is mixed with 'y' units of food-2, how dietician recommendation can be expressed ? (A) 20x+10y≤45;5x+2y≥25;3x+4y≤15;2x+5y≥15;x≥0;y≥0 (B) 20x+10y≤25;5x+2y≥45;3x+4y≤15;2x+5y≥15;x≥0;y≥0 (C) 20x+10y≥45;5x+2y≥25;3x+4y≥15;2x+5y≥15;x≥0;y≥0 (D) 20x+10y≤45;5x+2y≤25;3x+4y≤15;2x+5y≤15;x≥0;y≥0
Carbs Protein Fat Fibre Food-1 20 5 3 2 Food-2 10 2 4 5 ›Reveal solutionSolution
"At least" ⇒ every constraint is ≥; build one inequality per nutrient from the table, plus non-negativity.
Step 1 — Interpret "at least"
The mixture must contain AT LEAST the stated units, so each nutrient total ≥ its minimum.
Step 2 — Form one constraint per nutrient
With x units of Food-1 and y units of Food-2:
Nutrient Constraint Carbs (min 45) 20x+10y≥45 Protein (min 25) 5x+2y≥25 Fat (min 15) 3x+4y≥15 Fibre (min 15) 2x+5y≥15 Step 3 — Add non-negativity
Quantities cannot be negative: x≥0, y≥0.
This is exactly option (C). …
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