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Worked Examples · Example 8

Q.If 18!+19!=x10!\dfrac{1}{8!} + \dfrac{1}{9!} = \dfrac{x}{10!}, find xx.

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The key idea is to rewrite the fractions with a common denominator using factorial arithmetic. The value of xx is 100100.

Why This Works

Factorials grow fast — 10!10! is ten times 9!9!, and 9!9! is nine times 8!8!. When you see sums of reciprocals of factorials, the cleanest path is to express everything over the largest factorial in the equation. Here, that's 10!10!. Once you do, the algebra becomes simple arithmetic.

Step-by-Step

  1. Write the target denominator. We want everything in terms of 10!10!. Notice:

    • 10!=10×9!10! = 10 \times 9!
    • 9!=9×8!9! = 9 \times 8!
  2. Convert 18!\frac{1}{8!} to denominator 10!10!.

    Since 10!=10×9×8!10! = 10 \times 9 \times 8!, we multiply numerator and denominator:

18!=10×910×9×8!=9010!\frac{1}{8!} = \frac{10 \times 9}{10 \times 9 \times 8!} = \frac{90}{10!}

  1. Convert 19!\frac{1}{9!} to denominator 10!10!. Since 10!=10×9!10! = 10 \times 9!, we get:

19!=1010×9!=1010!\frac{1}{9!} = \frac{10}{10 \times 9!} = \frac{10}{10!}

  1. Add the two fractions. Now they share the denominator 10!10!:

18!+19!=9010!+1010!=10010!\frac{1}{8!} + \frac{1}{9!} = \frac{90}{10!} + \frac{10}{10!} = \frac{100}{10!}

  1. Compare with the given equation. …

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