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Exercise 1.4 · Q8

Q.Which of the following pairs of sets are disjoint

(i) {1, 2, 3, 4} and {x : x is a natural number and 4 ≤ x ≤ 6 }
(ii) { a, e, i, o, u } and { c, d, e, f }
(iii) {x : x is an even integer } and {x : x is an odd integer}
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Two sets are disjoint when they share no common elements. Check each pair by listing elements and looking for overlap: (i) shares 4, so not disjoint;

(ii) shares e, so not disjoint;

(iii) no integer can be both even and odd, so disjoint.

The concept of disjoint sets is beautifully simple: two sets are disjoint if their intersection is empty, meaning they have absolutely nothing in common. Think of it as two circles that never touch. To determine whether sets are disjoint, we need to examine their elements carefully and ask: is there even one element that belongs to both?

Let me work through each pair systematically.

(i) {1,2,3,4}\{1, 2, 3, 4\} and {x:x is a natural number and 4≤x≤6}\{x : x \text{ is a natural number and } 4 \le x \le 6\}

  1. Write out the second set explicitly. The natural numbers satisfying 4≤x≤64 \le x \le 6 are simply 4,5,64, 5, 6. So the second set is {4,5,6}\{4, 5, 6\}.

  2. Look for common elements. The first set contains 1,2,3,41, 2, 3, 4. The second contains 4,5,64, 5, 6. The element 44 appears in both sets.

  3. Conclude. Since the intersection {1,2,3,4}∩{4,5,6}={4}≠∅\{1, 2, 3, 4\} \cap \{4, 5, 6\} = \{4\} \neq \emptyset, these sets are not disjoint.

(ii) {a,e,i,o,u}\{a, e, i, o, u\} and {c,d,e,f}\{c, d, e, f\}

  1. Identify the sets. The first set contains the five vowels. The second set contains four consonants and one vowel.

  2. Spot the overlap. The letter ee appears in both sets.

  3. Conclude. The intersection is {e}≠∅\{e\} \neq \emptyset, so these sets are not disjoint.

Watch out

A common mistake is to assume sets with "different themes" (vowels vs. consonants) must be disjoint. Always check the actual elements — one exception breaks disjointness.

(iii) {x:x is an even integer}\{x : x \text{ is an even integer}\} and {x:x is an odd integer}\{x : x \text{ is an odd integer}\} …

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