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NCERT Exemplar · Q37

Q.The point (4,1)(4,1) undergoes the following two successive transformations:

(i) Reflection about the line y=xy=x
(ii) Translation through a distance 2 units along the positive xx-axis. Then the final coordinates of the point are
(A) (4,3)(4,3)
(B) (3,4)(3,4)
(C) (1,4)(1,4)
(D) (72,72)\left(\dfrac{7}{2},\dfrac{7}{2}\right)
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Reflection about y=xy = x swaps coordinates; translation shifts horizontally. Starting from (4,1)(4,1), we reflect to (1,4)(1,4) then translate 2 units right to reach (3,4)(3,4).

Understanding the transformations

When a point undergoes a reflection about the line y=xy = x, the geometric effect is a swap: every point (a,b)(a, b) maps to (b,a)(b, a). You can visualize this by imagining the line y=xy = x as a mirror at 45°45° through the origin—points on opposite sides exchange their xx and yy roles.

Translation along the positive xx-axis simply means adding to the xx-coordinate while leaving yy unchanged. A translation of 2 units right takes (p,q)(p, q) to (p+2,q)(p+2, q).

We apply these two transformations in sequence to the point (4,1)(4, 1).


Step-by-step solution

  1. Apply the reflection about y=xy = x The original point is (4,1)(4, 1). Under reflection about y=xy = x, we swap the coordinates:

(4,1)→reflect(1,4).(4, 1) \xrightarrow{\text{reflect}} (1, 4).

The point is now at (1,4)(1, 4). …

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