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NCERT Exemplar · Q18

Q.The value of Henry's constant KHK_H is _____________.

(i) greater for gases with higher solubility.
(ii) greater for gases with lower solubility.
(iii) constant for all gases.
(iv) not related to the solubility of gases.
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Henry's constant KHK_H measures how reluctant a gas is to dissolve: the larger KHK_H, the higher the pressure needed to force a given amount into solution, meaning lower solubility. The answer is (ii).

Henry's Law connects the partial pressure of a gas above a liquid to its concentration (or mole fraction) in the liquid at equilibrium. The law is usually written as

p=KH xp = K_H \, x

where pp is the partial pressure of the gas, xx is its mole fraction in solution, and KHK_H is Henry's constant for that particular gas–solvent pair at a given temperature.

The key insight is to understand what KHK_H means physically. Rearranging the equation gives

x=pKHx = \frac{p}{K_H}

This tells us that for a fixed partial pressure pp, a larger KHK_H produces a smaller mole fraction xx in solution. In other words, you need more pressure to dissolve the same amount of gas when KHK_H is large. That's the signature of a gas that doesn't want to dissolve easily—low solubility.

Conversely, a gas with high solubility dissolves readily even at low pressure, which corresponds to a small KHK_H.

KH=pxK_H = \frac{p}{x}

Henry's constant is the ratio of partial pressure to mole fraction; high KHK_H means high pressure is needed for a given dissolved amount.

Let's walk through the options:

  1. Option (i): greater for gases with higher solubility.

    If a gas is highly soluble, a small pressure suffices to dissolve a large amount, so xx is large for small pp. That makes KH=p/xK_H = p/x small, not large. This contradicts the claim.

  2. Option (ii): greater for gases with lower solubility.

    A poorly soluble gas requires high pressure to achieve even a modest mole fraction in solution. The ratio p/xp/x is therefore large, meaning KHK_H is large. This matches our physical reasoning perfectly. …

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