Q.Show that the relation R in the set A of all the books in a library of a college, given by and have same number of pages is an equivalence relation.
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Start your 14-day free trial to unlock the full solution →The relation groups books by their page count. It is an equivalence relation because it satisfies reflexivity (every book has the same number of pages as itself), symmetry (if book has the same page count as , then has the same as ), and transitivity (if matches and matches in page count, then matches ). Thus partitions the set of books into equivalence classes based on page count.
Why this works — the core idea
An equivalence relation is just a way of saying "these things are the same in some specific way." Here, the "way" is having the same number of pages. The three properties — reflexivity, symmetry, transitivity — are the minimal checks to ensure that this "sameness" behaves consistently. If any one fails, the grouping breaks down.
Let’s verify each property step by step.
1. Reflexivity: Every book relates to itself
For any book in the library, the number of pages in is obviously equal to the number of pages in . So for every .
This is trivially true — no book can have a different page count from itself.
Reflexivity is often the easiest to check, but don't skip it: some relations (like "is taller than") fail here because no one is taller than themselves.
2. Symmetry: If relates to , then relates to
Take any two books and such that . By definition, this means and have the same number of pages.
But "same number" is a symmetric statement: if has the same page count as , then automatically has the same page count as . So as well.
Symmetry holds whenever the defining condition is an equality or a mutual property. For example, "has the same birthday as" is symmetric; "is older than" is not.
3. Transitivity: If relates to and relates to , then relates to …
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