Q.If a binary operation is defined by a * b = a^b then 2 * 2 is equal to:
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Binary Operations
A binary operation ∗ on a set S assigns to each ordered pair (a,b) an element a∗b∈S (closure). Its algebraic properties are:
- Commutative: a∗b=b∗a for all a,b.
- Associative: (a∗b)∗c=a∗(b∗c) for all a,b,c.
- Identity element e: a∗e=e∗a=a for all a.
- Inverse of a: an element a′ with a∗a′=a′∗a=e.
To analyse a given rule such as a∗b=2a+b or a∗b=a+b+ab, check each property directly. For a∗b=a+b+ab: it is commutative and associative, the identity solves a+e+ae=a⇒e=0, and the inverse solves a+a′+aa′=0⇒a′=−1+aa.
Exam questions define an operation on R (or a subset) and ask whether it is commutative/associative, or to find its identity and inverse elements. …
The operation is defined as the first number raised to the power of the second, so evaluating it just means substituting the two values into that …
Substituting into the given binary operation a * b = a^b gives 2 * 2 = 2^2 = 4.
The binary operation is defined as a∗b=ab.
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Showing the 12 most recent of 28 on this concept.
- CBSE 2026Set A1 markMCQQ.If the operation ∗ is defined as a∗b=a+2b, then (2∗3)∗4 is(a) 30(b) 20(c) 16(d) 15
›Reveal solutionSolution
Apply the binary operation twice: 2∗3=8, then 8∗4=16.
Given a∗b=a+2b. Compute the inner operation first:
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- CBSE 2026Set A1 markMCQQ.If operation ∗ is defined as a∗b=a3+b3, then 4∗(1∗2)=(a) 729(b) 793(c) 783(d) 792
›Reveal solutionSolution
Evaluate the inner operation first (BODMAS with the defined ∗).
Given a∗b=a3+b3:
- Inner: 1∗2=13+23=1+8=9. …
- CBSE 2025Set E1 markMCQQ.If operation 'o' is defined as (a∘b)=a3+b3, then 4∘(1∘2)=(a) 729(b) 793(c) 783(d) 792
›Reveal solutionSolution
Evaluate the inner bracket first: 1∘2=9, then 4∘9=793.
The operation is a∘b=a3+b3. Compute the inner one first:
1∘2=13+23=1+8=9.
Then …
- CBSE 2025Set E1 markMCQQ.If operation 'o' is defined as (a∘b)=a2+b2−ab, then (1∘2)∘3=(a) 18(b) 27(c) 9(d) 12
›Reveal solutionSolution
Inner bracket 1∘2=3, then 3∘3=9.
The operation is a∘b=a2+b2−ab. Compute the inner bracket first:
1∘2=12+22−(1)(2)=1+4−2=3.
Then …
- CBSE 2025Set ANNUAL1 markMCQQ.If ab = a²+b² ∀a,b∈IN, then (45)*3 is equal to(a) 50(b) 60(c) 1230(d) 1690
›Reveal solutionSolution
Apply the binary operation a∗b=a2+b2 twice, from the inside out.
The symbol ∗ is a binary operation on N defined by a∗b=a2+b2. To evaluate (4∗5)∗3 we must first evaluate the inner operation, then use that result as the left operand of the outer operation.
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- CBSE 2025Set ANNUAL1 markMCQQ.Subtraction is not a binary operation in :(a) N(b) R(c) Q(d) Z
›Reveal solutionSolution
A binary operation on a set must be closed on that set; subtraction fails closure only on N among the four choices, since a smaller natural number minus a larger one is negative.
- A binary operation ∗ on a set S requires a∗b∈S for every a,b∈S (closure).
- Test subtraction on N={1,2,3,…}: take a=2,b=5. Then a−b=2−5=−3, which is not a natural number, so −3∈/N.
- Hence subtraction is NOT closed on N, so it is not a binary operation on N. …
- CBSE 2024Set D1 markMCQQ.If the operation ∗ is defined as a∗b=2a+b, then (2∗3)∗4 is(a) 30(b) 20(c) 18(d) 15
›Reveal solutionSolution
(2∗3)∗4=18.
The binary operation is defined by a∗b=2a+b. Work from the innermost bracket first.
Step 1: 2∗3=2(2)+3=4+3=7.
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- CBSE 2023Set M1 markQ.Let ∗ be the binary operation on N of natural numbers given by a∗b=LCM of a and b. Find 5∗7.
›Reveal solutionSolution
Tests a binary operation defined as LCM; 5∗7=35.
By definition a∗b=LCM(a,b). Since 5 and 7 are both prime (hence coprime), their LCM is their prod …
- CBSE 2023Set E1 markMCQQ.If the operation 'o' is defined as aob=3a+b then (2o3)o5=(a) 28(b) 32(c) 36(d) 22
›Reveal solutionSolution
(2o3)o5=32.
Using aob=3a+b:
…
- CBSE 2023Set ANNUAL1 markMCQQ.For any operation ∗, defined on 0 as a∗b=3a+b, then 1∗2=(a) 3(b) 1(c) 0(d) none of these
›Reveal solutionSolution
Substitute directly into the given binary operation formula.
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- CBSE 2023Set ANNUAL1 markMCQQ.The operation ∗ defined by a∗b=7ab is not a binary operation on :(a) R(b) Q+(c) C(d) Z
›Reveal solutionSolution
A binary operation must map back into the same set; testing a∗b=ab/7 on each option finds it fails closure only on the integers.
- For ∗ to be a binary operation on a set S, we need a∗b=7ab∈S for every a,b∈S (closure).
- On R: a,b real ⇒ab/7 real. Closed.
- On Q+: a,b positive rationals ⇒ab/7 is a positive rational. Closed. …
- CBSE 2023Set ANNUAL1 markMCQQ.Let * be a binary operation on the set of all non-zero real numbers, defined by a * b = ab/5. The value of x given that 2 * (x * 5) = 10 is –(a) 25(b) 30(c) 40(d) 50
›Reveal solutionSolution
Using a∗b=ab/5 repeatedly: first find x∗5, then apply the operation with 2 to solve for x.
Given a∗b=5ab and 2∗(x∗5)=10.
First compute the inner operation:
x∗5=5x⋅5=x.
So the equation becomes …
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