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Q.Using Ampere's circuital law, derive an expression for magnetic field intensity due to an infinitely long current carrying wire at a point at distance 'r' from it.

(OR)
A horizontal overhead power line carries a current of 90 A in east to west direction. What is the magnitude and direction of the magnetic field due to this current at a point 1.5 m below the power line ?
Punjab PsebPSEB Punjab Class 12 Board 2023Subjective· 3mImportance★★★★★
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By Ampere's law with a circular loop of radius r, the field of a long straight wire is B = mu0 I / (2 pi r).

Ampere's circuital law: The line integral of the magnetic field around any closed loop equals mu0 times the current enclosed:

integral of B . dl = mu0 I(enclosed).

Choice of Amperian loop: For an infinitely long straight wire, symmetry tells us the field has the same magnitude at every point a distance r from the wire and is directed tangentially (along circles around the wire). So choose a circular loop of radius r centred on the wire, in the plane perpendicular to it.

Applying the law: Along this circle, B is constant in magnitude and everywhere parallel to dl, so

integral of B . dl = B x (circumference) = B x (2 pi r).

The current enclosed is I. Ampere's law then gives: …

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