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NCERT Exemplar · Q30

Q.Suggest a route for the preparation of nitrobenzene starting from acetylene?

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To prepare nitrobenzene from acetylene, first cyclize three molecules of acetylene to form benzene, then nitrate benzene using a mixture of concentrated nitric and sulphuric acids. The final product is nitrobenzene.

Preparing nitrobenzene from acetylene involves two main conceptual transformations: first, building an aromatic ring from an alkyne, and second, introducing a nitro group onto that aromatic ring. Acetylene (C2H2\text{C}_2\text{H}_2) is a simple alkyne, while nitrobenzene is an aromatic compound with a −NO2-\text{NO}_2 group. The most straightforward approach is to first synthesize benzene from acetylene, and then perform an electrophilic aromatic substitution reaction (nitration) on benzene.

Here is the step-by-step route:

  1. Formation of Benzene from Acetylene (Cyclic Polymerisation/Aromatisation)

    The first step is to convert acetylene into benzene. This is achieved through a cyclic polymerisation reaction, also known as trimerisation. Three molecules of acetylene combine to form one molecule of benzene.

    • Reasoning: Acetylene is a highly unsaturated compound. Under specific conditions, its triple bonds can rearrange to form a stable aromatic ring structure. This reaction is a classic method for synthesizing benzene from alkynes.
    • Conditions: This reaction requires passing acetylene through a red-hot iron tube (or copper tube) heated to approximately 400∘C400^\circ\text{C}.
    • Reaction:

3CH≡CH→Red hot iron tube,400∘CC6H63\text{CH}\equiv\text{CH} \xrightarrow{\text{Red hot iron tube}, 400^\circ\text{C}} \text{C}_6\text{H}_6

    (Acetylene) (Benzene)

2. Nitration of Benzene to Nitrobenzene

Once benzene is formed, the next step is to introduce a nitro group onto the benzene ring. This is a classic example of an electrophilic aromatic substitution reaction.

*   **Reasoning:** Benzene is an electron-rich aromatic system, making it susceptible to attack by electrophiles. The nitronium ion ($\text{NO}_2^+$) acts as the electrophile in this reaction.
*   **Reagents:** A mixture of concentrated nitric acid ($\text{HNO}_3$) and concentrated sulphuric acid ($\text{H}_2\text{SO}_4$) is used. This mixture is often called the "nitrating mixture."
*   **Role of Sulphuric Acid:** Concentrated sulphuric acid acts as a catalyst. It protonates nitric acid, leading to the formation of the highly electrophilic nitronium ion ($\text{NO}_2^+$).
    $$ \text{HNO}_3 + 2\text{H}_2\text{SO}_4 \rightleftharpoons \text{NO}_2^+ + \text{H}_3\text{O}^+ + 2\text{HSO}_4^- $$ …

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