Q.In which C–C bond of CH₃CH₂CH₂Br, the inductive effect is expected to be the least?
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Start your 14-day free trial to unlock the full solution →The inductive effect weakens exponentially with distance from the electron-withdrawing group. The C₂–C₃ bond (farthest from Br) experiences the least inductive effect.
Understanding the Inductive Effect
The inductive effect is the transmission of charge through a chain of atoms by electrostatic induction. When an electronegative atom like bromine attaches to a carbon chain, it pulls electron density toward itself through the -bonds. This creates a polarisation that propagates along the chain, but crucially, it diminishes rapidly with each successive bond.
Think of it like ripples in a pond: the disturbance is strongest at the point of impact and fades as you move away. In , bromine is the "impact point."
Analyzing Each C–C Bond
Let's label the carbons for clarity:
where is directly bonded to bromine.
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The C₁–C₂ bond (between and )
This bond is immediately adjacent to the bromine. The electron-withdrawing effect here is strongest because bromine directly polarises the bond. The atom becomes significantly electron-deficient (), creating substantial polarisation in this bond.
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The C₂–C₃ bond (between the middle and terminal )
This bond is two positions removed from bromine. The inductive effect must travel through first, then through , before reaching this bond. At each step, the effect attenuates—typically by a factor of about per bond. By the time the electron-withdrawing influence reaches the bond, it is considerably weakened. …
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