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Worked Examples · Example 8.15

Q.In which C–C bond of CH₃CH₂CH₂Br, the inductive effect is expected to be the least?

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The inductive effect weakens exponentially with distance from the electron-withdrawing group. The C₂–C₃ bond (farthest from Br) experiences the least inductive effect.

Understanding the Inductive Effect

The inductive effect is the transmission of charge through a chain of atoms by electrostatic induction. When an electronegative atom like bromine attaches to a carbon chain, it pulls electron density toward itself through the σ\sigma-bonds. This creates a polarisation that propagates along the chain, but crucially, it diminishes rapidly with each successive bond.

Think of it like ripples in a pond: the disturbance is strongest at the point of impact and fades as you move away. In CHX3CHX2CHX2Br\ce{CH3CH2CH2Br}, bromine is the "impact point."

Analyzing Each C–C Bond

Let's label the carbons for clarity:

CX3HX3−CX2HX2−CX1HX2−Br\ce{C_3H3 - C_2H2 - C_1H2 - Br}

where CX1\ce{C_1} is directly bonded to bromine.

  1. The C₁–C₂ bond (between CHX2Br\ce{CH2Br} and CHX2\ce{CH2})

    This bond is immediately adjacent to the bromine. The electron-withdrawing effect here is strongest because bromine directly polarises the CX1−CX2\ce{C_1-C_2} bond. The CX1\ce{C_1} atom becomes significantly electron-deficient (δ+\delta^+), creating substantial polarisation in this bond.

  2. The C₂–C₃ bond (between the middle CHX2\ce{CH2} and terminal CHX3\ce{CH3})

    This bond is two positions removed from bromine. The inductive effect must travel through CX1\ce{C_1} first, then through CX2\ce{C_2}, before reaching this bond. At each step, the effect attenuates—typically by a factor of about 13\frac{1}{3} per bond. By the time the electron-withdrawing influence reaches the CX2−CX3\ce{C_2-C_3} bond, it is considerably weakened. …

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