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Exercises · 2.47

Q.Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate

(a) the frequency of emission,
(b) distance traveled by this radiation in 30 s,
(c) energy of quantum and
(d) number of quanta present if it produces 2 J of energy.
Rajasthan RbseTextbookSubjective· 3mImportance★★★★★est
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  1. ν=4.87×1014 Hz\nu = 4.87 \times 10^{14}\ \text{Hz};
  2. d=9.00×109 md = 9.00 \times 10^{9}\ \text{m};
  3. E=3.23×10−19 JE = 3.23 \times 10^{-19}\ \text{J};
  4. N=6.19×1018N = 6.19 \times 10^{18} quanta.

Given λ=616 nm=616×10−9 m\lambda = 616\ \text{nm} = 616 \times 10^{-9}\ \text{m}, c=3.00×108 m s−1c = 3.00 \times 10^{8}\ \text{m s}^{-1}, h=6.626×10−34 J sh = 6.626 \times 10^{-34}\ \text{J s}.

  1. Frequency from c=νλc = \nu\lambda:

    ν=cλ=3.00×108616×10−9=4.87×1014 Hz\nu = \frac{c}{\lambda} = \frac{3.00 \times 10^{8}}{616 \times 10^{-9}} = 4.87 \times 10^{14}\ \text{Hz}

  2. Distance in 30 s — all EM radiation travels at cc:

    d=c t=(3.00×108)(30)=9.00×109 md = c\,t = (3.00 \times 10^{8})(30) = 9.00 \times 10^{9}\ \text{m}

  3. Energy of one quantum from E=hνE = h\nu: …

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