Q.The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination(s) has/have the same energy list them: 1. n = 4, l = 2, = -2, = ; 2. n = 3, l = 2, = 1, = ; 3. n = 4, l = 1, = 0, = ; 4. n = 3, l = 2, = -2, = ; 5. n = 3, l = 1, = -1, = ; 6. n = 4, l = 1, = 0, = .
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Start your 14-day free trial to unlock the full solution →The energy of an electron in a multi-electron atom depends primarily on the principal quantum number and the azimuthal quantum number via the rule. For equal , the lower gives lower energy. Applying this rule, the increasing order of energies is: 5 < 2 = 4 < 3 = 6 < 1. Electrons 2 and 4 have the same energy; electrons 3 and 6 have the same energy.
The key idea here is that in multi-electron atoms, the simple hydrogen-like energy ordering (where energy depends only on ) breaks down due to electron-electron repulsion and shielding. The rule (also called the Aufbau principle or Madelung rule) gives the correct ordering for filling orbitals: lower means lower energy; if is equal, lower means lower energy.
Let’s apply this step by step.
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Identify the value for each electron.
For electron 1: , → .
For electron 2: , → .
For electron 3: , → .
For electron 4: , → .
For electron 5: , → .
For electron 6: , → .
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Order by first.
The smallest is 4 (electron 5). Next comes (electrons 2, 3, 4, 6). The largest is (electron 1). So electron 5 has the lowest energy, and electron 1 has the highest.
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Resolve ties using .
Among electrons with , we compare :
- Electrons 2 and 4 have .
- Electrons 3 and 6 have . Since lower gives lower energy when is equal, electrons 2 and 4 are lower in energy than electrons 3 and 6.
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Check for identical energies. …
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