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Q.Write the polar form of the complex number 1+2i1−3i\dfrac{1+2i}{1-3i}.

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2018Subjective· 4mImportance★★★★★
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Rationalise the fraction to get zz in a+bia+bi form, then compute its modulus and argument.

Multiply numerator and denominator by the conjugate of the denominator, (1+3i)(1+3i):

1+2i1−3i×1+3i1+3i=(1+2i)(1+3i)12+32=1+3i+2i+6i210=1+5i−610=−5+5i10=−12+12i\dfrac{1+2i}{1-3i} \times \dfrac{1+3i}{1+3i} = \dfrac{(1+2i)(1+3i)}{1^2+3^2} = \dfrac{1+3i+2i+6i^2}{10} = \dfrac{1+5i-6}{10} = \dfrac{-5+5i}{10} = -\dfrac{1}{2}+\dfrac{1}{2}i

So z=−12+12iz = -\dfrac{1}{2} + \dfrac{1}{2}i.

Modulus: r=(−12)2+(12)2=14+14=12=12r = \sqrt{\left(-\dfrac12\right)^2 + \left(\dfrac12\right)^2} = \sqrt{\dfrac14+\dfrac14} = \sqrt{\dfrac12} = \dfrac{1}{\sqrt2}

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