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Q.The amplitude (argument) of the complex number Z=−3+iZ=-\sqrt3+i will be:

(a) π6\dfrac{\pi}{6}
(b) 5π6\dfrac{5\pi}{6}
(c) −π6-\dfrac{\pi}{6}
(d) −5π6-\dfrac{5\pi}{6}
Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2023MCQ· 1mImportance★★★★★
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The argument of Z=−3+iZ=-\sqrt3+i is 5π6\dfrac{5\pi}{6}.

Here Z=x+iyZ=x+iy with x=−3x=-\sqrt3 (negative) and y=1y=1 (positive), so ZZ lies in the second quadrant.

The reference angle α\alpha satisfies tan⁡α=∣y∣∣x∣=13\tan\alpha = \dfrac{|y|}{|x|} = \dfrac{1}{\sqrt3}, so α=π6\alpha=\dfrac{\pi}{6}.

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