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Q.Convert the complex number −1+i-1+i into polar form.

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2023Subjective· 3mImportance★★★★★
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The polar form of −1+i-1+i is 2(cos⁡3π4+isin⁡3π4)\sqrt2\left(\cos\dfrac{3\pi}{4}+i\sin\dfrac{3\pi}{4}\right).

For z=−1+iz=-1+i, we have x=−1x=-1, y=1y=1.

Modulus: r=x2+y2=(−1)2+12=2r=\sqrt{x^2+y^2}=\sqrt{(-1)^2+1^2}=\sqrt2.

Argument: since x<0x<0 and y>0y>0, zz lies in the second quadrant. The reference angle satisfies tan⁡α=∣y∣∣x∣=11=1\tan\alpha=\dfrac{|y|}{|x|}=\dfrac11=1, so α=π4\alpha=\dfrac{\pi}{4}. In the second quadrant:

θ=π−α=π−π4=3π4\theta = \pi-\alpha = \pi-\frac{\pi}{4}=\frac{3\pi}{4}

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