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Worked Examples · Example 4
Q.

Find the mean deviation about the mean for the following data:

xix_ifif_i
22
58
610
87
108
125
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✓ Free question

For this frequency distribution the mean is xˉ=7.5\bar{x}=7.5, and the mean deviation about the mean is 9240=2.3\dfrac{92}{40}=2.3.

For discrete grouped data each value xix_i occurs fif_i times, so we weight every absolute deviation by its frequency. This mean-deviation calculation is a frequently tested part of NCERT Class 11 Maths Statistics.

Step 1 — Find the mean.

xˉ=∑fixi∑fi\bar{x}=\frac{\sum f_i x_i}{\sum f_i}

xix_ifif_ifixif_i x_i
224
5840
61060
8756
10880
12560
Total40300

xˉ=30040=7.5.\bar{x}=\frac{300}{40}=7.5.

Step 2 — Absolute deviations and their frequency-weighted values.

xix_ifif_i∣xi−7.5∣\lvert x_i-7.5\rvertfi∣xi−7.5∣f_i\lvert x_i-7.5\rvert
225.511
582.520
6101.515
870.53.5
1082.520
1254.522.5
Total4092

Step 3 — Mean deviation.

M.D.(xˉ)=∑fi∣xi−xˉ∣∑fi=9240=2.3.\text{M.D.}(\bar{x})=\frac{\sum f_i\lvert x_i-\bar{x}\rvert}{\sum f_i}=\frac{92}{40}=2.3.

Tip

Use the exact mean (7.57.5, not a rounded value) when finding the deviations, otherwise small rounding errors accumulate.

✓Final answer

The mean deviation about the mean is 2.32.3.

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