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NCERT Exemplar · Q12

Q.Four pressure–volume–temperature graphs for a fixed mass of gas are given, and you must decide which of them correctly depict ideal-gas behaviour. (More than one option may be correct.) The four graphs are: graph

(a) — volume VV (vertical axis) versus temperature TT (horizontal axis) at constant pressure, drawn as a straight line passing through the origin; graph
(b) — pressure PP (vertical axis) versus volume VV (horizontal axis) at constant temperature, drawn as a straight line with negative slope; graph
(c) — pressure PP (vertical axis) versus temperature TT (horizontal axis) at constant volume, drawn as a straight line passing through the origin; graph
(d) — the product PVPV (vertical axis) versus temperature TT (horizontal axis), drawn as a horizontal straight line (constant PVPV). Which graph(s) represent ideal-gas behaviour?
(a) graph (a): VV versus TT at constant PP, a straight line through the origin
(b) graph (b): PP versus VV at constant TT, a straight line of negative slope
(c) graph (c): PP versus TT at constant VV, a straight line through the origin
(d) graph (d): PVPV versus TT, a horizontal line
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Testing each graph against PV=nRTPV = nRT: graphs (a) and (c) match the law (both are V∝TV\propto T and P∝TP\propto T straight lines through the origin), while (b) should be a hyperbola not a straight line, and (d) should be a rising line not a flat one. So only (a) and (c) are correct.

Concept

Every graph must be consistent with the ideal-gas equation PV=nRTPV = nRT for a fixed mass of gas.

Testing each graph

  • Graph (a) — VV vs TT at constant PP: rearranging, V=(nR/P)TV = (nR/P)T, so V∝TV \propto T, a straight line through the origin. This matches the graph ✓.
  • Graph (b) — PP vs VV at constant TT: here P=nRT/VP = nRT/V, so P∝1/VP \propto 1/V, which is a rectangular hyperbola, not a straight line of negative slope. The graph is wrong ✗.
  • Graph (c) — PP vs TT at constant VV: P=(nR/V)TP = (nR/V)T, so P∝TP \propto T, a straight line through the origin. This matches the graph ✓. …

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