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NCERT Exemplar · Q5

Q.Conservation of momentum in a collision between particles can be understood from

(a) conservation of energy.
(b) Newton's first law only.
(c) Newton's second law only.
(d) both Newton's second and third law.
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Momentum conservation in collisions follows from Newton's second and third laws working together: the second law connects force to momentum change, while the third law ensures internal forces cancel. The answer is (D).

Why momentum is conserved during collisions

When two particles collide, they exert forces on each other. To understand why their total momentum stays constant, we need to trace how Newton's laws govern the exchange.

Newton's second law tells us that force changes momentum. For any particle,

F=dpdtF = \frac{dp}{dt}

where pp is momentum. This connects the force acting on a body to how quickly its momentum changes.

Newton's third law tells us that forces come in pairs. When particle 1 exerts force F⃗12\vec{F}_{12} on particle 2, particle 2 simultaneously exerts force F⃗21\vec{F}_{21} on particle 1, with

F⃗21=−F⃗12\vec{F}_{21} = -\vec{F}_{12}

These are the action-reaction pair, equal in magnitude and opposite in direction.

Now watch what happens when we combine them.

The derivation

  1. Apply the second law to each particle.

    For particle 1: F⃗21=dp⃗1dt\vec{F}_{21} = \frac{d\vec{p}_1}{dt}

    For particle 2: F⃗12=dp⃗2dt\vec{F}_{12} = \frac{d\vec{p}_2}{dt}

  2. Add the two equations.

F⃗21+F⃗12=dp⃗1dt+dp⃗2dt\vec{F}_{21} + \vec{F}_{12} = \frac{d\vec{p}_1}{dt} + \frac{d\vec{p}_2}{dt}

  1. Invoke the third law.

    Since F⃗21=−F⃗12\vec{F}_{21} = -\vec{F}_{12}, the left side vanishes:

0=d(p⃗1+p⃗2)dt0 = \frac{d(\vec{p}_1 + \vec{p}_2)}{dt}

  1. Conclude.

    The total momentum P⃗=p⃗1+p⃗2\vec{P} = \vec{p}_1 + \vec{p}_2 has zero rate of change, so it remains constant throughout the collision. …

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