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Q.What do you understand by damped oscillation?

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2026Subjective· 2mImportance★★★★★
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Concept understanding — Damped Oscillations

Damped Oscillations: When Motion Fades

Imagine pushing a child on a swing. You give one big push, then step back. The swing goes high, then lower, then lower still, until eventually it stops. That is a damped oscillation in everyday life. The swing wants to keep swinging forever — that would be an ideal, undamped oscillation — but something is stealing its energy. Air resistance, friction at the pivot, even the slight bending of the ropes all act as a brake.

The key intuition: the system still oscillates, but each swing is a little smaller than the last. The amplitude does not drop suddenly; it shrinks in a smooth, predictable way — exponentially.


The Physics: Where Does the Energy Go?

In an ideal oscillator (like a mass on a spring with no friction), the total mechanical energy is constant. Kinetic energy converts to potential energy and back, forever. The equation of motion is:

md2xdt2+kx=0m\frac{d^2x}{dt^2} + kx = 0

where mm is mass, kk is spring constant, and xx is displacement.

Now add a resistive force. The simplest model is a force proportional to velocity, like air drag at low speeds or the friction in a dashpot (a piston in oil). That force is:

Fdamping=−bv=−bdxdtF_{\text{damping}} = -b v = -b \frac{dx}{dt}

where bb is the damping coefficient — a positive number that measures how strong the resistive force is. The minus sign means the force always opposes the motion.

Newton's second law then becomes:

md2xdt2+bdxdt+kx=0m\frac{d^2x}{dt^2} + b\frac{dx}{dt} + kx = 0

That is the damped harmonic oscillator equation. It is the precise statement.


The Solution: Exponential Decay of Amplitude

The solution to this differential equation depends on how strong the damping is. For the most common case — underdamping — the system still oscillates, and the displacement is:

x(t)=A0e−b2mtcos⁡(ω′t+ϕ)x(t) = A_0 e^{-\frac{b}{2m}t} \cos(\omega' t + \phi)

Here is what each piece means:

  • A0A_0 is the initial amplitude.
  • e−b2mte^{-\frac{b}{2m}t} is the exponential decay factor. As time tt increases, this factor shrinks from 1 toward 0. The quantity b2m\frac{b}{2m} is often written as γ\gamma (the damping constant) or β\beta.
  • cos⁡(ω′t+ϕ)\cos(\omega' t + \phi) is the oscillatory part, with a new angular frequency ω′\omega' that is slightly less than the natural frequency ω0=k/m\omega_0 = \sqrt{k/m}:

ω′=ω02−(b2m)2\omega' = \sqrt{\omega_0^2 - \left(\frac{b}{2m}\right)^2}

Important

The amplitude of a damped oscillation decays as A(t)=A0e−b2mtA(t) = A_0 e^{-\frac{b}{2m}t}. The energy, which is proportional to amplitude squared, decays as E(t)=E0e−bmtE(t) = E_0 e^{-\frac{b}{m}t}.


Three Regimes of Damping

Not all damped systems oscillate. The value of bb relative to the critical value bc=2kmb_c = 2\sqrt{km} decides the behaviour:

RegimeConditionBehaviour
Underdampedb<2kmb < 2\sqrt{km}Oscillates with decaying amplitude
Critically dampedb=2kmb = 2\sqrt{km}Returns to equilibrium fastest, no oscillation
Overdampedb>2kmb > 2\sqrt{km}Returns slowly, no oscillation
Note

Critical damping is the sweet spot for things like door closers and car shock absorbers — you want the system to settle to zero as quickly as possible without bouncing.


Why Exponential? The Intuition …

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