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Q.A) Write structural formula of oxalic acid.
B) Explain mechanism of Aldol condensation. OR A) Write structural formula of Diethyl ketone.
B) Explain mechanism of Kolbe electrolysis.

Rajasthan RbseRajasthan Board Senior Secondary Examination 2019Subjective· 3mImportance★★★★★
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Oxalic acid is the simplest dicarboxylic acid, HOOC-COOH; aldol condensation is a base-catalysed reaction where one aldehyde's alpha-carbanion attacks the carbonyl carbon of another, giving a beta-hydroxy carbonyl product that can dehydrate to an unsaturated carbonyl compound.

A) Structural formula of oxalic acid:

Oxalic acid (ethanedioic acid) is the simplest dicarboxylic acid, with two -COOH groups directly bonded to each other:

HOOC-COOH (i.e. HO-CO-CO-OH)

B) Mechanism of Aldol condensation:

Aldol condensation occurs between two molecules of an aldehyde (or ketone) possessing at least one alpha-hydrogen, in the presence of dilute base (e.g. dil. NaOH). Taking acetaldehyde (CH3CHO) as an example:

Step 1 (formation of carbanion/enolate): The base (OH-) abstracts an acidic alpha-hydrogen atom from one molecule of CH3CHO, generating a resonance-stabilised carbanion (enolate ion): (-)CH2-CHO <-> CH2=CH-O(-)

Step 2 (nucleophilic addition): This carbanion (nucleophile) attacks the electrophilic carbonyl carbon of a SECOND molecule of CH3CHO, forming a new C-C bond and giving an alkoxide ion: CH3-CH(O-)-CH2-CHO

Step 3 (protonation): The alkoxide ion is protonated by water, regenerating the OH- catalyst and giving the beta-hydroxy aldehyde (the 'aldol'): CH3-CH(OH)-CH2-CHO (3-hydroxybutanal)

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