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Q.0.05M solution of K4[Fe(CN)6] at 300K is 92% dissociated. Calculate the osmotic pressure of the solution. (R = 0.0821 atm. LK^-1 mol^-1)

Rajasthan RbseRajasthan Board Senior Secondary Examination 2019Subjective· 2mImportance★★★★★
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Because K4[Fe(CN)6] dissociates into 5 ions, its van't Hoff factor must be included in the osmotic-pressure formula pi = i C R T.

K4[Fe(CN)6] dissociates as:

K4[Fe(CN)6] -> 4K+ + [Fe(CN)6]4-

This gives n = 5 ions per formula unit on complete dissociation.

Given degree of dissociation, alpha = 92% = 0.92

Van't Hoff factor:

i = 1 + alpha(n - 1) = 1 + 0.92 x (5 - 1) = 1 + 0.92 x 4 = 1 + 3.68 = 4.68

Osmotic pressure formula (with dissociation): pi = i C R T

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