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Exercise 9.3 · Q19

Q.The volume of spherical balloon being inflated changes at a constant rate. If initially its radius is 3 units and after 3 seconds it is 6 units. Find the radius of balloon after tt seconds.

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The radius after tt seconds is r(t)=(63t+27)1/3r(t)=(63t+27)^{1/3} units.

The volume of a sphere is V=43πr3V=\dfrac{4}{3}\pi r^3, and it changes at a constant rate, so dVdt=k\dfrac{dV}{dt}=k for some constant kk.

Integrate. Since ddt ⁣(43πr3)=k\dfrac{d}{dt}\!\left(\dfrac{4}{3}\pi r^3\right)=k,

43πr3=kt+C.\frac{4}{3}\pi r^3=kt+C.

Use the two data points.

  • At t=0,  r=3t=0,\;r=3: 43π(27)=C⇒C=36π\dfrac{4}{3}\pi(27)=C\Rightarrow C=36\pi.
  • At t=3,  r=6t=3,\;r=6: 43π(216)=3k+36π⇒288π=3k+36π⇒k=84π\dfrac{4}{3}\pi(216)=3k+36\pi\Rightarrow 288\pi=3k+36\pi\Rightarrow k=84\pi. …

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