Skip to content
Worked Examples · Example 9

Q.Find the distance between the parallel lines 15x+8y−34=015x + 8y - 34 = 0 and 15x+8y+31=015x + 8y + 31 = 0.

Sikkim CbseNCERTSubjective· 2mImportance★★★★★est
78% · 31/40 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Use the standard distance formula between two parallel lines ax+by+c1=0ax+by+c_1=0 and ax+by+c2=0ax+by+c_2=0.

d=∣c1−c2∣a2+b2d = \frac{|c_1-c_2|}{\sqrt{a^2+b^2}}

  1. Identify the coefficients. Both lines have the same a,ba,b (confirming they are parallel):

15x+8y−34=0 (c1=−34),15x+8y+31=0 (c2=31)15x+8y-34=0 \ (c_1=-34), \qquad 15x+8y+31=0 \ (c_2=31)

a=15,b=8a=15, \quad b=8

  1. Compute a2+b2\sqrt{a^2+b^2}.

152+82=225+64=289=17\sqrt{15^2+8^2} = \sqrt{225+64} = \sqrt{289} = 17

  1. Compute ∣c1−c2∣|c_1-c_2|.

∣c1−c2∣=∣−34−31∣=∣−65∣=65|c_1-c_2| = |-34-31| = |-65| = 65

  1. Apply the distance formula.

d=6517d = \frac{65}{17}

  1. Numeric value. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.