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Exercise 1.2 · Q2

Q.Compute zz, z2z^2, z3z^3, z−1z^{-1} for the following zz: 1−i1 - i, 3+i3 + i, 4+6i4 + 6i, 9+2i2+9i\dfrac{9 + 2i}{2 + 9i}, 1+πi1 + \pi i, 3+6 i\sqrt{3} + \sqrt{6}\,i.

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Each z2,z3z^2,z^3 is found by direct multiplication using i2=−1i^2=-1, and each z−1z^{-1} by z−1=zˉ/∣z∣2z^{-1}=\bar z/|z|^2 (or zˉ\bar z itself when ∣z∣=1|z|=1).

[!FORMULA]

(a+bi)(c+di)=(ac−bd)+(ad+bc)i(a+bi)(c+di)=(ac-bd)+(ad+bc)i; z−1=zˉa2+b2\quad z^{-1}=\dfrac{\bar z}{a^2+b^2} for z=a+bi≠0z=a+bi\ne0.

  1. z=1−iz=1-i: z2=(1−i)2=1−2i+i2=−2iz^2=(1-i)^2=1-2i+i^2=-2i. z3=z2⋅z=−2i(1−i)=−2i+2i2=−2−2iz^3=z^2\cdot z=-2i(1-i)=-2i+2i^2=-2-2i. z−1=1+i12+12=1+i2=0.5+0.5iz^{-1}=\dfrac{1+i}{1^2+1^2}=\dfrac{1+i}{2}=0.5+0.5i.
  2. z=3+iz=3+i: z2=9+6i+i2=8+6iz^2=9+6i+i^2=8+6i. z3=(8+6i)(3+i)=24+8i+18i+6i2=18+26iz^3=(8+6i)(3+i)=24+8i+18i+6i^2=18+26i. z−1=3−i10=0.3−0.1iz^{-1}=\dfrac{3-i}{10}=0.3-0.1i.
  3. z=4+6iz=4+6i: z2=16+48i+36i2=−20+48iz^2=16+48i+36i^2=-20+48i. z3=(−20+48i)(4+6i)=−80−120i+192i+288i2=−368+72iz^3=(-20+48i)(4+6i)=-80-120i+192i+288i^2=-368+72i. z−1=4−6i16+36=4−6i52=113−326iz^{-1}=\dfrac{4-6i}{16+36}=\dfrac{4-6i}{52}=\dfrac{1}{13}-\dfrac{3}{26}i.
  4. z=9+2i2+9iz=\dfrac{9+2i}{2+9i}: rationalise, z=(9+2i)(2−9i)22+92=18−77i+1885=36−77i85z=\dfrac{(9+2i)(2-9i)}{2^2+9^2}=\dfrac{18-77i+18}{85}=\dfrac{36-77i}{85}. Since 362+772=1296+5929=7225=85236^2+77^2=1296+5929=7225=85^2, ∣z∣=1|z|=1. z2=362−2(36)(77)i+(77i)2852=1296−5544i−59297225=−4633−5544i7225≈−0.641−0.767iz^2=\dfrac{36^2-2(36)(77)i+(77i)^2}{85^2}=\dfrac{1296-5544i-5929}{7225}=\dfrac{-4633-5544i}{7225}\approx-0.641-0.767i. z3=z2⋅z=(−4633−5544i)(36−77i)7225×85=−593676+157157i614125≈−0.967+0.256iz^3=z^2\cdot z=\dfrac{(-4633-5544i)(36-77i)}{7225\times85}=\dfrac{-593676+157157i}{614125}\approx-0.967+0.256i (magnitude check: 0.9672+0.2562≈1.0000.967^2+0.256^2\approx1.000 ✓, consistent with ∣z∣=1|z|=1). Since ∣z∣=1|z|=1, z−1=zˉ=36+77i85z^{-1}=\bar z=\dfrac{36+77i}{85}.
  5. z=1+πiz=1+\pi i: z2=1+2πi+π2i2=(1−π2)+2πi≈−8.870+6.283iz^2=1+2\pi i+\pi^2i^2=(1-\pi^2)+2\pi i\approx-8.870+6.283i. z3=[(1−π2)+2πi](1+πi)=(1−3π2)+(3π−π3)i≈−28.609−21.582iz^3=[(1-\pi^2)+2\pi i](1+\pi i)=(1-3\pi^2)+(3\pi-\pi^3)i\approx-28.609-21.582i. ∣z∣2=1+π2≈10.870|z|^2=1+\pi^2\approx10.870; z−1=1−πi1+π2≈0.092−0.289iz^{-1}=\dfrac{1-\pi i}{1+\pi^2}\approx0.092-0.289i.
  6. z=3+6iz=\sqrt3+\sqrt6 i: z2=3+218i−6=−3+62i≈−3+8.485iz^2=3+2\sqrt{18}i-6=-3+6\sqrt2i\approx-3+8.485i. …

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