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Exercise 2.4 · Q11

Q.Shakuntala designed a toy car. Help her to find the area of the given below. [Figure: a composite car-shaped figure made of a central rectangle 12 cm long and 5 cm high, with two identical triangles attached to its left and right ends, each with slant side 13 cm; below the figure are four wheels shown as circles of diameter 2 cm each, evenly spaced.] (Both the triangles are identical)

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The car-shaped figure (a 12×512\times5 cm rectangle, two identical right triangles with slant side 13 cm, and four wheels of diameter 2 cm) has total area ≈132.57 cm².

Area(rectangle) =l×b=l\times b. A right triangle with one leg 55 cm and hypotenuse (slant side) 1313 cm has the other leg =132−52=\sqrt{13^2-5^2} (the well-known 5-12-13 Pythagorean triple), and Area =12×base×height=\tfrac12\times\text{base}\times\text{height}. Area(circle)=πr2=\pi r^2.

  1. Central rectangle: 1212 cm long ×\times 55 cm high ⇒\Rightarrow Area =12×5=60 cm2=12\times5=60\text{ cm}^2.
  2. Each end triangle attaches along the rectangle's 55 cm side, so one leg =5=5 cm; the slant side (hypotenuse) =13=13 cm.
  3. Other leg =132−52=169−25=144=12=\sqrt{13^2-5^2}=\sqrt{169-25}=\sqrt{144}=12 cm (5-12-13 right triangle).
  4. Area of one triangle =12×5×12=30 cm2=\dfrac12\times5\times12=30\text{ cm}^2; both identical triangles together =2×30=60 cm2=2\times30=60\text{ cm}^2.
  5. Car-body area (rectangle ++ 2 triangles) =60+60=120 cm2=60+60=120\text{ cm}^2. …

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