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Worked Examples · Example 1

Q.Evaluate

(i) 5!5!
(ii) 7!7!
(iii) 7!−5!7! - 5!
Sikkim CbseNCERTSubjective· 2mImportance★★★★★est
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✓ Free question

Compute the three factorials directly by multiplying down from each number to 11, then subtract.

For a positive integer nn, n!=n×(n−1)×(n−2)×⋯×2×1n! = n\times(n-1)\times(n-2)\times\cdots\times2\times1, with 0!=10! = 1.

  1. 5!=5×4×3×2×1=1205! = 5\times4\times3\times2\times1 = 120.
  2. 7!=7×6×5×4×3×2×1=50407! = 7\times6\times5\times4\times3\times2\times1 = 5040. (Check: 7!=7×6×5!=42×120=50407! = 7\times6\times5! = 42\times120 = 5040.)
  3. 7!−5!=5040−120=49207! - 5! = 5040 - 120 = 4920.
✓Final answer

5!=1205! = 120, 7!=50407! = 5040, 7!−5!=49207! - 5! = 4920

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