Skip to content
Exercise 5.1 · Q12

Q.The sum of first three terms of an A.P. is 48. If the product of the first and second term exceeds 4 times the third term by 12, find the A.P.

Sikkim CbseNCERTSubjective· 3mImportance★★★★★est
11% · 12/106 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Taking the three terms as a−d,a,a+da-d,a,a+d, the sum condition gives a=16a=16 and the product condition gives d=9d=9, so the A.P. is 7,16,25,…7,16,25,\ldots.

Three terms of an A.P. in symmetric form: a−d, a, a+da-d,\ a,\ a+d, with sum 3a3a.

  1. Let the first three terms be a−d, a, a+da-d,\,a,\,a+d. Their sum is 4848: (a−d)+a+(a+d)=3a=48⇒a=16(a-d)+a+(a+d)=3a=48\Rightarrow a=16.
  2. The product of the first and second term exceeds 4 times the third term by 12: (a−d)(a)=4(a+d)+12(a-d)(a)=4(a+d)+12.
  3. Substitute a=16a=16: 16(16−d)=4(16+d)+12⇒256−16d=64+4d+12=76+4d16(16-d)=4(16+d)+12\Rightarrow 256-16d=64+4d+12=76+4d.
  4. Solve: 256−76=4d+16d⇒180=20d⇒d=9256-76=4d+16d\Rightarrow 180=20d\Rightarrow d=9. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.