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Exercise 5.1 · Q5

Q.Which of the following terms is not a term of the A.P. −3,−7,−11,−15,…,−403,…,−799-3, -7, -11, -15, \ldots, -403, \ldots, -799?

(a) −500-500
(b) −399-399
(c) −503-503
(d) −51-51
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Each option is tested by solving the A.P.'s general-term equation for nn; a genuine term must give a positive integer index, so the option that fails this test is the odd one out.

General (nnth) term of an A.P.:

an=a+(n−1)da_n = a+(n-1)d

A number xx is a term of the A.P. iff n=x−ad+1n = \dfrac{x-a}{d}+1 is a positive integer.

  1. Identify the A.P.: −3,−7,−11,−15,…-3,-7,-11,-15,\ldots, so a=−3a=-3 and d=−7−(−3)=−4d=-7-(-3)=-4.
  2. Write the general term:

an=a+(n−1)d=−3+(n−1)(−4)=−3−4n+4=1−4na_n = a+(n-1)d = -3+(n-1)(-4) = -3-4n+4 = 1-4n

  1. Test option (a) −500-500: solve 1−4n=−500⇒4n=501⇒n=5014=125.251-4n=-500 \Rightarrow 4n = 501 \Rightarrow n=\dfrac{501}{4}=125.25 — not an integer, so −500-500 cannot be a term.
  2. Test option (b) −399-399: 1−4n=−399⇒4n=400⇒n=1001-4n=-399 \Rightarrow 4n=400 \Rightarrow n=100 — a positive integer, so −399-399 is a term.
  3. Test option (c) −503-503: 1−4n=−503⇒4n=504⇒n=1261-4n=-503 \Rightarrow 4n=504 \Rightarrow n=126 — a positive integer, so −503-503 is a term. …

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