Exercise 5.3 · Q3
Q.Which number should be added to the numbers 3, 8, 13 so that the resulting numbers are in G.P.?
(a) 4
(b) 2
(c) 5
(d)
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Start your 14-day free trial to unlock the full solution →As printed, 3, 8, 13 are already in AP so no constant addition can make a GP; solved on the standard 3, 7, 13 form of this question, gives the valid GP — matching option (c).
[!FORMULA] If is added to to form a GP:
= the three given numbers, = the number to be added.
- Apply the condition to the printed numbers : .
- Expand the left side: . Expand the right side: .
- Equating: — a contradiction, so no finite satisfies this for exactly 3, 8, 13.
- Reason: are already an AP (). Adding the same constant to every term of an AP keeps it an AP with the SAME common difference; a nonzero-common-difference AP can only equal a GP if that difference is 0 — so this specific triple can never be converted to a GP by adding a constant. …
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