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Exercise 5.2 · Q11

Q.If a,b,c,da, b, c, d are in G.P., show that

(i) a2+b2,b2+c2,c2+d2a^2+b^2, b^2+c^2, c^2+d^2 are in G.P.
(ii) 1a2+b2,1b2+c2,1c2+d2\dfrac{1}{a^2+b^2}, \dfrac{1}{b^2+c^2}, \dfrac{1}{c^2+d^2} are in G.P.
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Write everything in terms of a,ra,r and verify each middle-term-squared equals the product of the outer terms.

For x,y,zx,y,z in G.P., y2=xzy^2=xz. Since a,b,c,da,b,c,d are in G.P., b=ar, c=ar2, d=ar3b=ar,\,c=ar^2,\,d=ar^3.

  1. Since a,b,c,da,b,c,d are in G.P.: b=ar, c=ar2, d=ar3b=ar,\ c=ar^2,\ d=ar^3.
  2. Part (i): a2+b2=a2+a2r2=a2(1+r2)a^2+b^2=a^2+a^2r^2=a^2(1+r^2).
  3. b2+c2=a2r2+a2r4=a2r2(1+r2)b^2+c^2=a^2r^2+a^2r^4=a^2r^2(1+r^2).
  4. c2+d2=a2r4+a2r6=a2r4(1+r2)c^2+d^2=a^2r^4+a^2r^6=a^2r^4(1+r^2).
  5. Check the G.P. condition (b2+c2)2=(a2+b2)(c2+d2)(b^2+c^2)^2=(a^2+b^2)(c^2+d^2): LHS =[a2r2(1+r2)]2=a4r4(1+r2)2=\left[a^2r^2(1+r^2)\right]^2=a^4r^4(1+r^2)^2.
  6. RHS =a2(1+r2)⋅a2r4(1+r2)=a4r4(1+r2)2=a^2(1+r^2)\cdot a^2r^4(1+r^2)=a^4r^4(1+r^2)^2. LHS == RHS, so a2+b2, b2+c2, c2+d2a^2+b^2,\ b^2+c^2,\ c^2+d^2 are in G.P. — (i) proved. …

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