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Exercise 3.2 · Q4

Q.Let A={1,2,{3,4},5}A = \{1, 2, \{3, 4\}, 5\}. Put the correct symbol in each of the following.

(i) {3,4}\{3, 4\} ___ AA
(ii) {1}\{1\} ___ AA
(iii) {3}\{3\} ___ AA
(iv) {{3,4}}\{\{3, 4\}\} ___ AA
(v) {1,3}\{1, 3\} ___ AA
(vi) {1,5}\{1, 5\} ___ AA
(vii) ϕ\phi ___ AA
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With A={1,2,{3,4},5}A=\{1,2,\{3,4\},5\} (4 elements, one of which is itself the set {3,4}\{3,4\}), each part checks whether the given object is an element of AA (∈\in) or a subset of AA (⊂\subset).

[!FORMULA] x∈Ax\in A means xx appears directly in the listing of AA. S⊂AS\subset A means every element of SS is also an element of AA. Note AA's four elements are exactly 1, 2, {3,4}, 51,\ 2,\ \{3,4\},\ 5 — the numbers 33 and 44 individually are not elements of AA.

  1. (i) {3,4}\{3,4\} ___ AA: {3,4}\{3,4\} is itself listed as one of the four elements of AA, so {3,4}∈A\{3,4\}\in A.

  2. (ii) {1}\{1\} ___ AA: 1∈A1\in A, so the singleton {1}⊂A\{1\}\subset A.

  3. (iii) {3}\{3\} ___ AA: for {3}⊂A\{3\}\subset A we'd need 3∈A3\in A, but AA's elements are 1,2,{3,4},51,2,\{3,4\},5 — the bare number 33 is not among them. So {3}⊄A\{3\}\not\subset A.

  4. (iv) {{3,4}}\{\{3,4\}\} ___ AA: this is the set whose only element is {3,4}\{3,4\}. Since {3,4}∈A\{3,4\}\in A (step i), the singleton {{3,4}}⊂A\{\{3,4\}\}\subset A.

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