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Exercises · 3.21

Q.Would you expect the second electron gain enthalpy of O as positive, more negative or less negative than the first? Justify your answer.

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The second electron gain enthalpy of oxygen is positive (endothermic), unlike the first which is negative. Adding an electron to O⁻ requires energy because you're forcing a negatively charged electron into an already negative ion against strong electrostatic repulsion.

Why electron gain enthalpy changes sign

Electron gain enthalpy measures the energy change when an isolated gaseous atom gains an electron. The first electron gain enthalpy of oxygen is negative—the process releases energy—because the incoming electron experiences the strong nuclear attraction of 8 protons and completes a more stable electronic configuration.

But what happens when we try to add a second electron to form O²⁻? Now we're not dealing with a neutral atom anymore. We're pushing an electron into an ion that already carries a full negative charge.

The electrostatic reality

  1. First electron addition: O(g) → O⁻(g)

    The neutral oxygen atom has 8 protons in the nucleus attracting the incoming electron. Yes, there's some repulsion from the existing 8 electrons, but the net effect is attractive. The electron configuration goes from 1s2 2s2 2p41s^2 \, 2s^2 \, 2p^4 to 1s2 2s2 2p51s^2 \, 2s^2 \, 2p^5, moving closer to the stable noble gas configuration. Energy is released: ΔegH1=−141 kJ mol−1\Delta_{eg}H_1 = -141 \, \text{kJ mol}^{-1}.

  2. Second electron addition: O⁻(g) → O²⁻(g)

    Now the species already has a net negative charge. The incoming electron faces:

    • Attraction from the 8 protons (still there, unchanged)
    • Strong repulsion from the 9 electrons already present, especially the extra electron that made O⁻ negative

    The repulsion dominates. You're essentially trying to compress two like charges together. This requires an input of energy—the process is endothermic.

Watch out

A common mistake is thinking "more electrons = more stable = more energy released." Stability depends on the balance between nuclear attraction and electron-electron repulsion. Once an ion becomes negatively charged, adding more electrons fights against electrostatic repulsion.

  1. The energy cost …

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