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Worked Examples · Example 4

Q.Solve 5−2x3≤x6−5\dfrac{5 - 2x}{3} \le \dfrac{x}{6} - 5.

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Clear the fractions, gather the xx-terms so the coefficient stays positive, and solve. The solution is x≥8x \ge 8.

Clear fractions. The LCD of 33 and 66 is 66:

6⋅5−2x3≤6⋅x6−6⋅5  ⟹  2(5−2x)≤x−30.6\cdot\frac{5-2x}{3} \le 6\cdot\frac{x}{6} - 6\cdot 5 \;\Longrightarrow\; 2(5-2x) \le x-30.

Expand.

10−4x≤x−30.10 - 4x \le x - 30.

Collect xx-terms on the right (keeps the coefficient positive, so no sign flip). Add 4x4x to both sides:

10≤5x−30.10 \le 5x - 30.

Isolate xx. Add 3030: …

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