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Exercise 5.1 · Q6

Q.3x−7>5x−13x - 7 > 5x - 1

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The inequality 3x−7>5x−13x - 7 > 5x - 1 simplifies to x<−3x < -3. The solution set is all real numbers less than −3-3, i.e., (−∞,−3)(-\infty, -3).

Why This Works: The Logic of Linear Inequalities

A linear inequality is like a balance scale — but instead of finding a single weight that balances it, you find a whole range of weights that keep one side heavier. The key rule: whatever you do to one side, you must do to the other. The only twist is that multiplying or dividing by a negative number flips the inequality sign. Why? Because if a>ba > b, then −a<−b-a < -b — think of it as reflecting the number line.

Here, we have 3x−7>5x−13x - 7 > 5x - 1. The goal is to isolate xx on one side. Let's walk through it.

  1. Bring variable terms together. Subtract 5x5x from both sides:

3x−7−5x>5x−1−5x3x - 7 - 5x > 5x - 1 - 5x

This gives:

−2x−7>−1-2x - 7 > -1

Why subtract 5x5x? Because it moves the xx terms to the left, making it easier to isolate xx.

  1. Isolate the term with xx. Add 77 to both sides to remove the constant on the left:

−2x−7+7>−1+7-2x - 7 + 7 > -1 + 7

So:

−2x>6-2x > 6

Notice: adding/subtracting never flips the inequality sign.

  1. Divide by the coefficient of xx — and watch the sign. Divide both sides by −2-2. Since −2-2 is negative, the inequality sign flips:

−2x−2<6−2\frac{-2x}{-2} < \frac{6}{-2}

This yields:

x<−3x < -3

Watch out

A classic mistake: forgetting to flip the inequality when dividing by a negative number. If you wrote x>−3x > -3, you'd be wrong. Always check: if you multiply or divide by a negative, the inequality reverses.

  1. Interpret the solution. …

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