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NCERT Exemplar · Q19
Q.

The weights of coffee in 70 jars is shown in the following table:

Weight (in grams)Frequency
200 - 20113
201 - 20227
202 - 20318
203 - 20410
204 - 2051
205 - 2061

Determine variance and standard deviation of the above distribution.

Sikkim CbseLong· 5mImportance★★★★★est
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Taking the assumed mean A=202.5A = 202.5 (step h=1h = 1), the variance is σ2≈1.16 g2\sigma^2 \approx 1.16\ \text{g}^2 and the standard deviation is σ≈1.08 g\sigma \approx 1.08\ \text{g}.

Step 1: Midpoints and step deviations ui=xi−202.5u_i = x_i - 202.5

Weight (g)xix_ifif_iuiu_ifiuif_iu_ifiui2f_iu_i^2
200–201200.513−2-2−26-2652
201–202201.527−1-1−27-2727
202–203202.51800000
203–204203.51011101010
204–205204.5122224
205–206205.5133339

N=∑fi=70N = \sum f_i = 70,  ∑fiui=−38\ \sum f_iu_i = -38,  ∑fiui2=102\ \sum f_iu_i^2 = 102.

Step 2: Variance

σ2=h2[∑fiui2N−(∑fiuiN)2]\sigma^2 = h^2\left[\frac{\sum f_iu_i^2}{N} - \left(\frac{\sum f_iu_i}{N}\right)^2\right] …

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