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NCERT Exemplar · Q37

Q.The following information relates to a sample of size 60: ∑x2=18000\sum x^2 = 18000, ∑x=960\sum x = 960 The variance is
(A) 6.63
(B) 16
(C) 22
(D) 44

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Variance measures the average squared deviation from the mean. Using the computational formula σ2=∑x2n−(∑xn)2\sigma^2 = \frac{\sum x^2}{n} - \left(\frac{\sum x}{n}\right)^2, we find the variance is 44.

The variance quantifies how spread out the data points are from their mean. While the definitional formula σ2=∑(xi−xˉ)2n\sigma^2 = \frac{\sum (x_i - \bar{x})^2}{n} captures the concept directly—average of squared deviations—it's computationally tedious when you have raw data summaries. That's where the computational formula shines: it lets you calculate variance directly from ∑x\sum x and ∑x2\sum x^2 without finding every individual deviation.

The computational formula is:

σ2=∑x2n−(∑xn)2\sigma^2 = \frac{\sum x^2}{n} - \left(\frac{\sum x}{n}\right)^2

This expands to "mean of squares minus square of mean," a pattern worth memorizing for quick calculations.

Let me work through this step by step with the given information.

1. Identify what we know

We have:

  • Sample size: n=60n = 60
  • Sum of observations: ∑x=960\sum x = 960
  • Sum of squared observations: ∑x2=18000\sum x^2 = 18000

2. Calculate the mean

The mean is simply the sum divided by the count:

xˉ=∑xn=96060=16\bar{x} = \frac{\sum x}{n} = \frac{960}{60} = 16

3. Calculate the mean of squares

This is the average of all the squared values:

∑x2n=1800060=300\frac{\sum x^2}{n} = \frac{18000}{60} = 300

4. Apply the computational formula

Now substitute into the variance formula: …

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