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Worked Examples · Example 16

Q.If AA, BB are symmetric matrices of same order, then what can be said for matrix AB−BAAB - BA?

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Using A′=AA' = A, B′=BB' = B and the reversal law (XY)′=Y′X′(XY)' = Y'X', the transpose of AB−BAAB-BA turns out to be its own negative, so AB−BAAB-BA is skew-symmetric.

A′=A,B′=B (symmetric),(XY)′=Y′X′,(X−Y)′=X′−Y′.A' = A,\quad B' = B \ (\text{symmetric}),\qquad (XY)' = Y'X',\qquad (X-Y)' = X' - Y'.

A matrix MM is skew-symmetric if M′=−MM' = -M.

  1. Let M=AB−BAM = AB - BA. Take the transpose:

M′=(AB−BA)′=(AB)′−(BA)′.M' = (AB - BA)' = (AB)' - (BA)'.

  1. Apply the reversal law (XY)′=Y′X′(XY)' = Y'X' to each term: M′=B′A′−A′B′.M' = B'A' - A'B'. …

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