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5.1 · Q7

Q.The average heart rate for Indians is 72 beats/minute. To lower their heart rate, a group of 25 people participated in an aerobics exercise programme. The group was tested after six months to see if the group had significantly slowed their heart rate. The average heart rate for the group was 69 beats/minute with a standard deviation of 6.5. Was the aerobics program effective in lowering heart rate?

Sikkim CbseNCERTSubjective· 5mImportance★★★★★
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A left-tailed one-sample tt-test gives t=−2.31t=-2.31; as ∣t∣>1.711|t|>1.711 we reject H0H_0, so the programme significantly reduced heart rate.

t=xˉ−μs/nt = \frac{\bar{x}-\mu}{s/\sqrt{n}}

  • xˉ=69\bar{x}=69 (group mean after programme), μ=72\mu=72 (national average), s=6.5s=6.5, n=25n=25.
  1. Hypotheses ("slowed / lowered" heart rate ⇒\Rightarrow left-tailed):

H0:μ=72H1:μ<72H_0:\mu=72 \qquad H_1:\mu<72

  1. Standard error: sn=6.525=6.55=1.3\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{25}}=\dfrac{6.5}{5}=1.3.
  2. Test statistic:

t=69−721.3=−31.3=−2.308.t=\frac{69-72}{1.3}=\frac{-3}{1.3}=-2.308.

  1. Critical value: d.f. =n−1=24=n-1=24, left-tailed α=0.05⇒tcrit=−1.711\alpha=0.05 \Rightarrow t_{crit}=-1.711. …

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