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Worked Examples · Example 3

Q.For scheduling three hour-long tasks (read, eat and nap) between the hours of 5 p.m. and 8 p.m. we have two degrees of freedom as any two tasks can be scheduled at will, but after two of them have been set in time slots, the time slot for the third is decided by default.

Sikkim CbseNCERTSubjective· 2mImportance★★★★★
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✓ Free question

Three one-hour tasks fill three one-hour slots (5–8 p.m.); two can be arranged freely and the third is fixed, giving n−1=2n-1=2 degrees of freedom.

Degrees of freedom=n−1\text{Degrees of freedom} = n - 1

  • nn = number of items being freely arranged
  • Subtracting 11 accounts for the single constraint that fixes the last item.
  1. There are three one-hour slots between 5 p.m. and 8 p.m. and three one-hour tasks, so n=3n=3.
  2. Any two of the tasks (read, eat, nap) can be assigned to slots at will.
  3. After two slots are filled, only one slot remains, so the third task's time is decided by default — no freedom.
  4. Therefore the number of free choices is

n−1=3−1=2.n-1 = 3-1 = 2.

✓Final answer

Degrees of freedom =n−1=3−1=2= n-1 = 3-1 = \mathbf{2}.

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