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Worked Examples · Example 6

Q.Country A has an average farm size of 191 acres, while Country B has an average farm size of 199 acres. Assume the data were attained from two samples with standard deviations of 38 and 12 acres and sample sizes of 8 and 10, respectively. Is it possible to infer that the average size of the farms in the two countries is different at α=0.05\alpha = 0.05? Assume that the populations are normally distributed.

Sikkim CbseNCERTSubjective· 5mImportance★★★★★
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A two-sample tt-test gives t=−0.57t=-0.57; as ∣t∣<2.365|t|<2.365 we cannot reject H0H_0, so the two countries' average farm sizes are not significantly different.

t=xˉ1−xˉ2s12n1+s22n2t = \frac{\bar{x}_1-\bar{x}_2}{\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}}

  • xˉ1,xˉ2\bar{x}_1,\bar{x}_2 = sample means; s1,s2s_1,s_2 = sample SDs; n1,n2n_1,n_2 = sample sizes
  • d.f. (conservative) =min⁡(n1−1, n2−1)=\min(n_1-1,\,n_2-1)
  1. Data: Country A: xˉ1=191\bar{x}_1=191, s1=38s_1=38, n1=8n_1=8. Country B: xˉ2=199\bar{x}_2=199, s2=12s_2=12, n2=10n_2=10.
  2. Hypotheses ("different" ⇒\Rightarrow two-tailed):

H0:μ1=μ2H1:μ1≠μ2H_0:\mu_1=\mu_2 \qquad H_1:\mu_1\neq\mu_2

  1. Standard error terms:

s12n1=3828=14448=180.5,s22n2=12210=14410=14.4.\frac{s_1^2}{n_1}=\frac{38^2}{8}=\frac{1444}{8}=180.5,\qquad \frac{s_2^2}{n_2}=\frac{12^2}{10}=\frac{144}{10}=14.4.

  1. Standard error: 180.5+14.4=194.9=13.96\sqrt{180.5+14.4}=\sqrt{194.9}=13.96.
  2. Test statistic: t=191−19913.96=−813.96=−0.573.t=\frac{191-199}{13.96}=\frac{-8}{13.96}=-0.573. …

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